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MCS 275 Spring 2024
Emily Dumas
Reminders and announcements:
A strategy that often involves recursion.
Not always possible or a good idea. It only works if merging partial solutions is easier than solving the entire problem.
















Problem: A list of length n is given. For any two elements you are allowed to ask which one is "smaller". Using this information, put the list in increasing order.
A divide-and-conquer solution to comparison sort.
Fast, often used in practice.
Key: Two sorted lists can be easily merged into one sorted list.
mergesort:
Input: list L whose elements support comparison.
Goal: return a list that contains the items from L but in sorted order.
L has 0 or 1 elements, return LL into rougly equal pieces L0 and L1.
mergesort on L0 and L1.merge to merge these sorted lists and return the result.
This algorithm depends on having a function merge that can merge two sorted lists into a
single sorted list.
merge:
Input: sorted lists L0 and L1.
Goal: return a sorted list with same items as L0+L1
Li0,i1 to keep track of current position in
L0,L1 respectively. Set to zero.
i0 < len(L0) and i1 < len(L1), do the following:
L0[i0] and L1[i1] is smaller.L.
i0,i1 was used.L0 to L.L1 to L.
Let's implement mergesort in Python.